mowmen200316 mowmen200316
  • 11-11-2020
  • Mathematics
contestada

The leg of an isosceles triangle has a length 2x+4 and the base has length 3x. The
perimeter is 141, What is the length of the base?

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 20-11-2020

Answer:

[tex]Base = 57[/tex]

Step-by-step explanation:

Given

[tex]Length = 2x + 4[/tex]

[tex]Base = 3x[/tex]

[tex]Perimeter = 141[/tex]

Required

Determine the length of the base

The perimeter of an isosceles triangle is:

[tex]Perimeter = 2*Length + Base[/tex]

[tex]141 = 2 (2x + 4) + 3x[/tex]

[tex]141 = 4x + 8 + 3x[/tex]

Collect Like Terms

[tex]4x + 3x = 141 - 8[/tex]

[tex]7x = 133[/tex]

Divide both sides by 7

[tex]x = 19[/tex]

To get the base, we substitute 19 for x in [tex]Base = 3x[/tex]

[tex]Base = 3 * 19[/tex]

[tex]Base = 57[/tex]

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