How many grams of 12 (molecular iodine) will be required to completely react with 35.20 ml of 0.150 M NaβSβO3 solution according to the balanced
equation below?
12 (s) + 2 NaβSβOβ (aq) β NaβS4O6 (aq) + 2 Nal (aq)
A.O 1.34 g of 1β
B.0.335 g of 1β
C.0.670 g of 12
D.0.751 g of 1β