Given 30 people, find the probability that among the twelve months there are 6 containing two birthdays and 6 containing 3. You can assume each month has an equal number of days.
a) 30! / (2¹2 * 3⁶ * 12!)
b) 30! / (2⁶ * 3⁶ * 12!)
c) 30! / (2¹2 * 3¹2 * 12!)
d) 30! / (2⁶ * 3¹2 * 12!)