Use the Laplace transform to solve the initial-value problem:
[y'+4y=3 cos(3x), y(0)=5]
a) y(x)=- 12/25 cos(3x) + 9/25 sin(3x) +137/25e⁴ˣ
b) y(x)= 113/25e⁻⁴ˣ + 12/25cos(3x)+9/25 sin(3x)
c) y(x)=-137/25 e⁻⁴ˣ+12/25 cos(3x) + 9/25 sin(3x)
d) y(x)=3 cos(3x) +5
e) y(x)=3 cos(3x)-5e⁴ˣ
f) None of the above.