How does h(t)= 1 2t change over the interval from t= – 10 to t= – 3?

I really need help
this is from IXLs section AA if anyone is wondering
the options are
a. h(t) decreases by a factor of 2^6
b. h(t) increases by a factor of 14
c. h(t) decreases 14%
d. h(t) decreases by a factor of 2^7