jennypay131 jennypay131
  • 12-04-2024
  • Physics
contestada

The energy of a linear harmonic oscillator is
E= p²ₓ/2m + Cx²/2
a. Show, using the uncertainty relation, that this can be written as
E= h²/32π²mx² +Cx²/2
b. Then show that the minimum energy of the oscillator is hv/2 where
v= (1/2π)√C/m
is the oscillatory frequency.

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