joshuaswag3319 joshuaswag3319
  • 10-06-2018
  • Mathematics
contestada

Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

Respuesta :

caylus
caylus caylus
  • 15-06-2018
Hello,
center is (4,-6)
radius=4
since
[tex]x^2-8x+y^2+12y+36=0\\ x^2-2*4x+16-16+y^2+2*6y+36=0\\ (x-4)^2+(y+6)^2=4^2 [/tex]


Answer Link

Otras preguntas

what happens to an alarm stage of stress response? increase blood pressure fluid loss blurred vision cramping leg muscles
What are the four main types of consumers?
If a highway loops around a city is 45 miles long. If exits are placed every 5 miles will the exits be evenly spaced around the loop? Explain answer
9+16*(6-5)/(7+9)-8 using pemdas
whats the answer two -3x+6=12
What is these decimal numbers from least to greatest
if 7y + 4 = -3 then what does y stand for
When you subtract one square number from another the answer is 5. What are the two square numbers?
33+8x=5(-6x-1) what is the work and answer
How can you use the word 'receptor' in a sentence? (cell biology)