Solution:
The given figure is two half circles inscribed inside a square of side 6 inch.
Diameter of half circles = 6 in
Radius of the half circles = [tex] \frac{6}{2} = 3 in [/tex]
The yellow region is symmetrical.
Area of the yellow region =[tex] \frac{1}{2} (Area of square - 2 ( Area of half circle)) [/tex]
= [tex] \frac{1}{2} (side^{2} - 2 (\frac{1}{2} \pi radius^{2} )) [/tex]
[tex] = \frac{1}{2} (6^2-2(\frac{1}{2} \pi 3^2)\\= \frac{1}{2} (36-9\pi )\\= \frac{1}{2}(7.725)\\=3.9 in^2 [/tex]
