luck6021 luck6021
  • 12-08-2018
  • Mathematics
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GEOMETRIC PROBABILITY URGENT?

GEOMETRIC PROBABILITY URGENT class=

Respuesta :

frika
frika frika
  • 12-08-2018

The shaded area is a sector. Find the area of whole circle and sector:

[tex] A_{circle}=\pi r^2,\\
A_{sector}=\dfrac{r^2\alpha}{2} =\dfrac{r^2\cdot \frac{106\pi}{180}}{2} =\dfrac{53\pi r^2}{180} [/tex].

Use the geometric probability to find the probability that point will be at the shaded region:

[tex] Pr=\dfrac{A_{shaded}}{A_{circle}} =\dfrac{\frac{53\pi r^2}{180} }{\pi r^2}=\dfrac{53}{180}=0.2944 [/tex].

In percent 0.2944 is 29.44% that is 29.4% rounded to the nearest tenth.

Answer: 29.4%

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