sophx
sophx sophx
  • 10-02-2019
  • Mathematics
contestada

14 a and b please !!!

14 a and b please class=

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jelly8bean
jelly8bean jelly8bean
  • 10-02-2019
14a

[tex] \frac{2}{3x - 2c} + ( - ( \frac{3}{2x - 3c} )) = \frac{7}{2c} [/tex]

[tex] \frac{2}{3x - 2c} - \frac{3}{3x - 2c} = \frac{7}{2c} [/tex]

[tex] \frac{2 - 3}{3x - 2c} = \frac{7}{2c} [/tex]

[tex] \frac{ - 1}{3x - 2c} = \frac{7}{2c} [/tex]

Next, cross-multiply.

[tex] - 2c = 21x - 14c[/tex]

[tex]12c = 21x[/tex]

[tex]x = \frac{7}{4} c= 1 \frac{3}{4} c[/tex]


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