Respuesta :

AlbertThomas

[tex] {3}^{ - 2x} = { (\frac{1}{ {3}^{2} } )}^{x} = ( { \frac{1}{9} )}^{x} an \\ exponential \: function \: of \: the \: form \\ f(x) = a \times {b}^{x} \: with \: a \: = 1 \: and \\ b = \frac{1}{9} [/tex]