ria2389
ria2389 ria2389
  • 12-04-2019
  • Mathematics
contestada

Plz help me with this

Plz help me with this class=

Respuesta :

tramserran
tramserran tramserran
  • 14-04-2019

Answer:  [tex]\bold{b)\quad \dfrac{-\sqrt{13}-5}{4}}[/tex]

Step-by-step explanation:

[tex]\dfrac{3}{\sqrt{13}-5}\bigg(\dfrac{\sqrt{13}+5}{\sqrt{13}+5}\bigg)\\\\\\=\dfrac{3(\sqrt{13}+5)}{13-25}\\\\\\=\dfrac{3(\sqrt{13}+5)}{-12}\\\\\\=\dfrac{\sqrt{13}+5}{-4}\\\\\\=\dfrac{-\sqrt{13}-5}{4}[/tex]

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