[tex](\frac{f}{g})(x)=\frac{x^{2} +2x-3}{x^2-9}[/tex] since x = 4, you plug in 4 into the x's in the equation
[tex](\frac{f}{g} )(4)=\frac{(4)^2+2(4)-3}{(4)^2-9} = \frac{16 + 8 - 3}{16 - 9}[/tex] Simplify
[tex]\frac{21}{7} =3[/tex]
so [tex](\frac{f}{g})(4)=3[/tex]
(f + g)(x) = (x² + 2x - 3) + (x² - 9) Plug in 4 for x
(f + g)(4) = 4² + 2(4) - 3 + (4)² - 9
(f + g)(4) = 16 + 8 - 3 + 16 - 9 = 28
