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  • 12-07-2019
  • Physics
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A force of 7.50N is applied to a spring whose spring constant is 0.289 N/cm. Find its change in length.​

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Аноним Аноним
  • 12-07-2019

Hook's law states that

[tex]F=k\Delta x[/tex]

where F is the applied force, k is the spring constant, and [tex]\Delta x[/tex] is the change in length.

Plugging your values, we have

[tex]7.5 = 0.289\Delta x \implies \Delta x = \dfrac{7.5}{0.289}\approx 25.95[/tex]

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