cecehardy143 cecehardy143
  • 12-08-2019
  • Mathematics
contestada

if DF=9x-39 and DE=47 and EF is 3x+10 find ef

Respuesta :

jimrgrant1 jimrgrant1
  • 12-08-2019

Answer:

EF = 58

Step-by-step explanation:

Starting with the premise that

DF = DE + EF, then

9x - 39 = 47 + 3x + 10 ( subtract 3x from both sides )

6x - 39 = 57 ( add 39 to both sides )

6x = 96 ( divide both sides by 6 )

x = 16

Hence

EF = 3x + 10 = (3 × 16) + 10 = 48 + 10 = 58

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