Answer:5.6m/s^2
Explanation: Since the initial velocity (u) was not given, it's assume that the train was at rest hence it's initial velocity (u) =0
From Newton's first equation of motion,
Where v=u+at ,where v= final velocity ,u = initial velocity, a= acceleration and t= time
Now given v= 45 u=0 t=8 and a=? Substituting the values into the equation, thus : 45= 0+8a making a the subject in the relation , a= 45/8 = 5.6m/s^2. As the acceleration of the train
