josskebpopstr
josskebpopstr
11-06-2016
Mathematics
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find the integral of 1/sqrt(x^2-9)
Respuesta :
Fluxions
Fluxions
15-06-2016
Let x = 3secβ, then dx = 3secβtanβ
∫dx/√(x²-9) = ∫[(3secβtanβ)/(3tanβ)]dβ
= ∫secβdβ
= ln |tanβ - secβ| + c
= ln |√(x² - 9)/3 - x/3| + C
= ln |√(x² - 9)/x| + C
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