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Use valence bond theory to describe the number and types of hybrid bonding orbitals on the central atom of each of the following. (a) BCl4− type of hybridization: sp-hybridization sp2-hybridization sp3-hybridization sp3d-hybridization sp3d2-hybridization In BCl4−, boron has hybrid orbital(s).

Respuesta :

Answer:

The central atom boron in BCl₄⁻ ion is sp³ hybridized and has 4 sp³ hybrid orbitals.

Explanation:

Boron is an element which belongs to group 13 of periodic table.

According to the Valence Bond Theory, in BCl₄⁻ ion, one 2s and three 2p orbitals of boron hybridize to form four sp³ hybrid orbitals, which overlap with four 2p orbitals of chlorine to form BCl₄⁻ anion.

Therefore, the central atom boron in BCl₄⁻ ion is sp³ hybridized and has 4 sp³ hybrid orbitals.

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