crpowell0101 crpowell0101
  • 12-12-2019
  • Mathematics
contestada

Which equation is the slope-intercept form of the line that passes through (12, 9) and is perpendicular to the graph of y = −34x + 1?

Respuesta :

nikishashrestha
nikishashrestha nikishashrestha
  • 18-12-2020

Answer:

slope(m)=-34 and

y-intercept (c)=417

Step-by-step explanation:

here,

the given equation of line is

34x+y-1=0.. eqn(i)

any line parallel to the line (i) is

34x+y+k=0...eqn(ii)

since, eqn(ii) passes through (12,9)[replacing x=12 and y=9 in eqn(ii),we get]

34*12+9+k=0

•°•k=-417

substituting the value of k=-417 in eqn(ii), we get

34x+y-417=0

now,

reducing it in slope intercept form,

y=-34x+417

comparing it with y=mx+c we get,

slope(m)=-34 and

y-intercept(c)=417

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