Answer:
remaining zeros are -i, -12-i
Step-by-step explanation:
Given that Degree 4; zeros: i, -12+i
complex zeros always occurs in pairs
the conjugate of a+ib is a-ib
the another zero of a+ib is a-ib
we are given with two zeros i and -12+i
the conjugate of 'i' is -i
the conjugate of -12+i is -12-i
so the other two zeros of the polynomial is
-i, -12-i
