Answer: [tex]x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}[/tex]
Step-by-step explanation:
[tex]2x^2-9x+5[/tex]
a=2
b=-9
c=5
[tex]x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)} }{2(2)}[/tex]
[tex]x=\frac{9\frac{+}{}\sqrt{81-40} }{4}[/tex]
[tex]x=\frac{9\frac{+}{}\sqrt{41} }{4}[/tex]
[tex]x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}[/tex]
