Answer:
AB = 15
A = 53º
B = 37º
Step-by-step explanation:
To find AB you can use pythagoream's theorem.
[tex]c^2=a^2+b^2\\c=\sqrt{a^2+b^2}[/tex]
[tex]c=\sqrt{(9)^2+(12)^2} \\c=\sqrt{81+144}\\ c=\sqrt{225}\\ c=15[/tex]
To find the angle A, use sine
[tex]sin=\frac{opposite}{hypothenuse}[/tex]
[tex]sin=\frac{12}{15}\\ sin^-^1=53[/tex]
To find B, remember that all of the angles of a triangle add up to 180º. If you already have 90º + 53º + x =180º
143º+x=180º
Subtract 143
x=180º-143º
x=37º
