Answer:
[tex]\bold{y+1=5(x+1)}[/tex]
Step-by-step explanation:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(-1,\,-1)\ \implies\ x_1=-1\,,\ y_1=-1\\(0,\,4)\ \implies\ x_2=0\,,\ y_2=4\\\\m=\dfrac{4-(-1)}{0-(-1)}=\dfrac{5}{1}=5[/tex]
[tex]y-y_1=m(x-x_1)[/tex] - point-slope form of Equation of the Line
[tex]x_1=-1\,,\ y_1=-1\,,\ m=5\\\\equation:\\{}\qquad\qquad y-(-1)=5\big(x-(-1)\big)\\\\{}\qquad\qquad y+1=5\big(x+1\big)[/tex]
