calyntanqh calyntanqh
  • 11-07-2020
  • Mathematics
contestada

The HCF of 56, x and 154 is 14 and their LCM is 4312. Find the smallest possible integer x

Respuesta :

PollyP52 PollyP52
  • 11-07-2020

Answer:

Smallest possible x = 98.

Step-by-step explanation:

4312 = 2 * 2 * 2 * 7 * 7 * 11

56 = 2 *2 * 2 * 7

154 = 2 * 7 * 11

Because the HCF is 14:-

x =   = 2 * 7 OR  2 * 7 * other prime number(s).

As there are 2 7's in the prime factors of 4312 there must also be another 7 in the prime factors of x.

x =  2 * 7 * 7 = 98.

Answer Link

Otras preguntas

Rewrite 3/100 as the sum of unit fractions
Which sentence is punctuated correctly? Puhlavi drove the kids to school, and went to work. Jamarius rode his bike to the restaurant but Amber skateboarded. Dia
What observation led researchers to propose that chloroplasts evolved from cyanobacteria?
what does more than mean
Use a case study to explain why a coastal habitat has distinct characteristics (8marks) please help!!!
What is the area of the triangle? A. 48 square meters B. 60 square meters C. 78 square meters D. 120 square meters
Which of the following Founding Fathers is described by this list? Colonial spokesperson in London after the passage of the Stamp Act Member of the Declaration
Darwin observed fossils of huge animals such as glyptodon a giant armadillo why were there fossils of interest to him
Solve the equation 3(x+2)=5x-2
What is the measure of the missing angle? Triangle with two angles labeled