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  • 10-08-2020
  • Mathematics
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answer of a ²-10a+16-6b-b^2​

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Аноним Аноним
  • 10-08-2020

[tex] \quad a^2-10a+16-6b-b^2[/tex]

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

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