10-09-2016
Mathematics

contestada

Need help solving this question B^3+1/27

Respuesta :

10-09-2016

Hello,

to solve we must have an equation.

If you mean factor then

[tex]b^3+ \dfrac{1}{3^3} =(b+ \dfrac{1}{3} )(b^2- \dfrac{b}{3} + \dfrac{1}{9}) [/tex]

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