citlalyvillasenor204 citlalyvillasenor204
  • 12-09-2020
  • Mathematics
contestada

how do i solve the equation [tex](2a^{3} b^{4}c^{0})^{3}[/tex]

Respuesta :

Estellia
Estellia Estellia
  • 12-09-2020

Answer:

[tex]8\frac{-2x}{-2}=\frac{0}{-2}[/tex]

Step-by-step explanation:

[tex]\left(2a^3b^4c^0\right)^3[/tex]

Cube each portion:

[tex]2^3\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8a^9\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8a^9b^{12}\left(c^0\right)^3[/tex]

[tex]8a^9b^{12}\times1[/tex]

[tex]8a^9b^{12}[/tex]

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