roycharlton01 roycharlton01
  • 11-11-2014
  • Mathematics
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How do you solve B(x) = 18-0.5x with x being -2, 0, 5

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Аноним Аноним
  • 11-11-2014
[tex]B(x)=18-0.5x\\\\x=-2\to B(-2)=18-0.5\times(-2)=18+1=19\\\\x=0\to B(0)=18-0.5\times0=18\\\\x=5\to B(5)=18-0.5\times5=18-2.5=15.5[/tex]
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