The resulting function for (f−g)(x) is 2x²+x-3
Let the required functions be:
f(x)=2x²+3x
g(x)=2x+3
We are required to find (f−g)(x).
(f−g)(x). = f(x) - g(x)
(f−g)(x) = 2x²+3x - (2x+3)
(f−g)(x) = 2x²+3x - 2x - 3
(f−g)(x) = 2x²+x-3
Hence the resulting function for (f−g)(x) is 2x²+x-3
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