alexprestwick alexprestwick
  • 12-10-2020
  • Mathematics
contestada

Given that 7 is a zero of h(x)=x^3-7x^2-3x+21, find the other zeros.

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 12-10-2020

Answer:

x= 7    x = ±√3

Step-by-step explanation:

h(x)=x^3-7x^2-3x+21

Factor by grouping

h(x) = x^2( x-7)  -3 (x-7)

Factor out an (x-7)

h(x) = (x-7)  ( x^2 -3)

Using the zero product property

0= (x-7)  ( x^2 -3)

x-7 =0     x^2 -3 =0

x=7     x^2 =3

x= 7    x = ±√3

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