JhSparrow JhSparrow
  • 10-12-2020
  • Mathematics
contestada

Please help, solve this question
[tex]\int\limits^\pi_\pi {\sin^2 3x \sec x^3 - \tan^5 x\cos 4x} \, dx[/tex]

Respuesta :

ramalmlki
ramalmlki ramalmlki
  • 10-12-2020

Answer:

[tex]\boxed{0}[/tex]

Step-by-step explanation:

[tex]\int\limits^a_a {f(x)} \, dx = 0[/tex]

.

So

[tex]\int\limits^\pi_\pi {\sin^2 3x \sec x^3 - \tan^5 x\cos 4x} \, dx[/tex]

[tex]= 0[/tex]

Answer Link
jackdaniel3s jackdaniel3s
  • 10-12-2020

the answer is zero. because the batas is same

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