Answer:
- 1 ≤ x ≤ [tex]\frac{5}{2}[/tex]
Step-by-step explanation:
Inequalities of the type | x | ≤ a , always have solutions of the form
- a ≤ x ≤ a
Given
| 4x - 3 | ≤ 7 , then
- 7 ≤ 4x - 3 ≤ 7 ( add 3 to the 3 intervals )
- 4 ≤ 4x ≤ 10 ( divide each interval by 4 )
- 1 ≤ x ≤ [tex]\frac{10}{4}[/tex] , that is
- 1 ≤ x ≤ [tex]\frac{5}{2}[/tex]
