Ptorrez2721 Ptorrez2721
  • 11-01-2021
  • Mathematics
contestada

Given z1 =9+9/3i and z2 = 2+/3i, what is z2-z1?


8+7/3i


-7-8/3i


7+ 10/3i


-7+ 10/3i

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 12-01-2021

Answer:

z2 - z1 = 7/3i

Step-by-step explanation:

Given the following complex number:

z1 = 9+i/3i

z2 =  2+i/3i,

Taking the difference

z2 - z1 = 9+i/3i - (2+i))/3i)

z2-z1 = (9+i-(2+i))/31

z2 - z1 = 9+i -2-i/3i

z2-z1 = 9-2/3i

z2 - z1 = 7/3i

Note that the complex number given was not properly written and the ones used were assumed. Same procedure an be used for other complex numbers that might be given.

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