Answer:
There are four nitrogenous bases that makes DNA. These are A, T, G and C. If a DNA strand has eight pairs of nitrogenous bases, the eight bases can be
1. AA GG TT CC
2. GC GG AT CG
3. AT TA GG GC
4. GA AG GC GG
If we have to make 8 pairs of bases, the number of possible sequences would be 4 to the power 8.
Answer: THERE WILL BE 65,536 DIFFERENT SEQUENCES OF 8 BASES.
Explanation:
