lexusleonard12345 lexusleonard12345
  • 12-01-2021
  • Physics
contestada

Using a force of 200N, a hockey player does 500 J of work horizontally
onto a puck that started from rest on frictionless ice. How far did the puck
travel?

Respuesta :

helinwang helinwang
  • 12-01-2021

Answer:

The displacement is 2.5 meters

Explanation:

The formula for work is: W = Fs, where "W" is work, "F" is force, and "s" is displacement.

Since displacement is the shortest distance from start to finish, and the puck travels in a straight line, in this case, displacement = distance traveled.

Let's apply the formula:

[tex]W = Fs\\500J = 200N s\\\frac{500J}{200N} = s\\2.5 m = s[/tex]

The displacement is 2.5 meters

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