The number of atoms :
C = 6 x 5 x 10²¹ = 3 x 10²²
H = 12 x 5 x 10²¹ = 6 x 10²²
O = 6 x 5 x 10²¹ = 3 x 10²²
Further explanation
Given
1.5 g glucose(C₆H₁₂O₆)
Required
The number of atoms
Solution
mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :
mol = mass : MW
mol = 1.5 : 180
mol = 0.0083
Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹
There are 6 C, 12 H and 6 O, so number or atoms :
C = 6 x 5 x 10²¹ = 3 x 10²²
H = 12 x 5 x 10²¹ = 6 x 10²²
O = 6 x 5 x 10²¹ = 3 x 10²²
