tayloraustin99 tayloraustin99
  • 10-02-2021
  • Chemistry
contestada

What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
raise the temperature from 22ᵒC to 33.6ᵒC?

Respuesta :

timo86
timo86 timo86
  • 15-02-2021

Answer:

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

[tex]t_{1}[/tex] = 22 °C

[tex]t_{2}[/tex] = 33,6 °C

Q = 202 J

The formula is: Q = c * m * ([tex]t_{2} - t_{1}[/tex])

c = [tex]\frac{Q}{m * (t_{2} - t_{1} )}[/tex]

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

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