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12-11-2016
Chemistry

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What is the molality of 151 grams of na2so4 dissolved in 547 g of water?

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Willchemistry Willchemistry

13-11-2016

Molar mass Na2SO4 => 142.04 g/mol

Number of moles:

n = sample mass / molar mass

n = 151 / 142.04 => 1.063 moles

Mass of solvent in kilograms :

1 kg = 1000 g

574 g / 1000 = 0.574 kg

Therefore:

b = n solute / m solvent

b = 1.063 / 0.547

b = 1.943 mol/kg

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