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Answer:
(f -g)(x) = -3x^3 +x^2 +2x
Step-by-step explanation:
We assume the expression for g(x) has a typo, and the first term should be 3x^3.
(f -g)(x) = f(x) -g(x) = (3x^2 -2x -9) -(3x^3 +2x^2 -4x -9)
= 3x^2 -2x -9 -3x^3 -2x^2 +4x +9
= -3x^3 +(3 -2)x^2 +(-2+4)x +(-9+9)
(f -g)(x) = -3x^3 +x^2 +2x
