Answer with Step-by-step explanation:
Let f(x)=y
⇒ x=[tex]f^{-1}(y)[/tex]
f(x)=2x+3=y
⇒ 2x+3=y
⇒ 2x=y-3
⇒ x=(y-3)/2
⇒ [tex]f^{-1}(y)=\dfrac{y-3}{2}[/tex]
Replacing y by x
⇒ [tex]f^{-1}(x)=\dfrac{x-3}{2}[/tex]
Hence, inverse of the function f(x)=2x+3 is:
[tex]f^{-1}(x)=\dfrac{x-3}{2}[/tex]
