Seudónimo Seudónimo
  • 12-06-2021
  • Mathematics
contestada

PLZZ HELP!!! I'll mark Brainliest! Thanks!!

PLZZ HELP Ill mark Brainliest Thanks class=

Respuesta :

Аноним Аноним
  • 12-06-2021

Answer:

[tex] { \cot}^{2} \theta - { \cos }^{2} \theta = { \cot }^{2} \theta { \cos }^{2} \theta \\ divide \: by \: { \cos }^{2} \theta : \\ \frac{1}{ { \sin }^{2}\theta } - 1 = { \cot}^{2} \theta \\ 1 - { \sin }^{2} \theta = { \cos }^{2} \theta \\ identity = > \: { \boxed{ { \sin}^{2} \theta + { \cos}^{2} \theta = 1}}[/tex]

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