junaycpt05
junaycpt05 junaycpt05
  • 10-09-2021
  • Mathematics
contestada

sin30. cot45/cos30. tan60​

Respuesta :

Аноним Аноним
  • 10-09-2021

Answer:

[tex] \frac{ \sin(30) \cot(45) }{ \cos(30) \tan(60) } \\ [/tex]

group them by simplifying:

[tex] = \{ \frac{ \sin(30) }{ \cos(30) } . \frac{ \cot(45) }{ \tan(60) } \} \\ \\ = \frac{ \tan(30) }{ \tan(45) \tan(60) } \\ \\ = \frac{( \frac{1}{ \sqrt{3} }) }{1 \times \sqrt{3} } \\ \\ = \frac{1}{ \sqrt{3} } \times \frac{1}{ \sqrt{3} } \\ \\ = \frac{1}{ {( \sqrt{3}) }^{2} } \\ \\ = { \boxed{ \boxed{ \frac{1}{3} }}}[/tex]

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