Annyohasayo
Annyohasayo Annyohasayo
  • 10-09-2021
  • Mathematics
contestada

find
[tex]y = \sqrt{ \frac{x + 7}{x - 2} } [/tex]
a)
[tex]x = 5[/tex]
b)
[tex]y = 4[/tex]
​

Respuesta :

askurdoubt
askurdoubt askurdoubt
  • 11-09-2021

Step-by-step explanation:

[tex]y = \sqrt{ \frac{x + 7}{x - 2} } \\ case1)x = 5 \\ y = \sqrt{ \frac{5 + 7}{5 - 2} } = \sqrt{ \frac{12}{3} } = \sqrt{4} = 2 \\ y = 2 \\ case2) \: y = 4 \\ 4 = \sqrt{ \frac{x + 7}{x - 2} } \\ squaring \: both \: side \\ {4}^{2} = { (\sqrt{ \frac{x + 7}{x - 2} } )}^{2} \\ 16 = \frac{ x + 7}{x - 2} \\ 16(x - 2) = x + 7 \\ 16x - 32 = x + 7 \\ 16x - x = 7 + 32\\ 15x = 39 \\ x = \frac{39}{15} = 2.6[/tex]

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