jr2d23cpo jr2d23cpo
  • 11-09-2021
  • Mathematics
contestada

PLEASE HELP I DONT GOT A LOT OF TIME

When $(x\sqrt{x^3})^4$ is simplified, what is the exponent of $x$?

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Wonderwoman16
Wonderwoman16 Wonderwoman16
  • 11-09-2021

Answer:

The answer is obviously (2³${data-answer}amp;8*9ⁿ+⁶7⅞)

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LammettHash
LammettHash LammettHash
  • 13-12-2021

We have

[tex]\sqrt{x^3} = x^{\frac32}[/tex]

so by applying the usual properties for exponents,

[tex]\left(x\sqrt{x^3}\right)^4 = \left(x \cdot x^{\frac32}\right)^4 = \left(x^{1+\frac32}\right)^4 = \left(x^{\frac52}\right)^4 = x^{\frac52\cdot4} = x^{\frac{20}2} = \boxed{x^{10}}[/tex]

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