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10-11-2021
Chemistry

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how many moles of iron are present in 3.15 × 10^24 atoms of iron?

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polyalchem polyalchem

13-11-2021

Answer:

5.23 moles

Explanation:

How many moles of iron are present in 3.15 × 10^24 atoms of iron?

1 mole has 6.02 X 10^23 particles

so

3.15X10^ 24 atoms =( 3.15 X 10^24)/(6.02 X 10^23) =(3.15/6.02 )X 10 =

5.23 moles

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