Cbennett88 Cbennett88

10-12-2021
Mathematics

contestada

solve 7e^(2x)-5>58. Round to the nearest hundredth.

Respuesta :

goddessboi goddessboi

10-12-2021

Answer:

[tex]x\gtrapprox1.1[/tex]

Step-by-step explanation:

[tex]7e^{2x}-5>58[/tex]

[tex]7e^{2x}>63[/tex]

[tex]e^{2x}>9[/tex]

[tex]2x>ln(9)[/tex]

[tex]x>\frac{ln(9)}{2}[/tex]

[tex]x\gtrapprox1.1[/tex]

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