janirac janirac

13-01-2022
Physics

contestada

How much work
was done to
accelerate a 2.2
kg object from
rest to 26m/s?

Respuesta :

AliFrost004 AliFrost004

13-01-2022

Answer:

Explanation:

work done = change in kinetic energy, assuming there are no energy losses.

work done = 1/2 × m × change in v^2

= 1/2 × 2.2 × ( 26^2 - 0^2)

= 1/2 × 2.2 × 676

= 743.6 joules

Answer Link

Otras preguntas

which rigid transformation can map abc on to fed

Ranger simplified this expression. 3(2.7x+5) -2(4x-1.6) What was rangers sonllified expression? A:0.1x+18.2 B:-16.1x+11.8 C:16x-18.2 D:-0.1x+11.8

Why are advanced features helpful when businesses use spreadsheets

a que hora salen ustedes para la escuela

HELP PLEASEEE!! BRAINLIEST GOES TO BEST ANSWER!!! Caption: Upward of 500 marchers crowd on steps and sidewalk in front of City Hall and sing after they staged a

You are 300 miles from home and you are driving toward home at an average of 55mph. Write an equation to represent the situation and find the domain and range o

If you were to make a cross section of the body through the diaphragm, which body cavities would you separate? Select one: a. Cranial/Spinal b. Abdominal/Pelvic

How do you write three times as many "m" as "s" algebraically, or in an equation form?

what is transformer and its function?

PLEASE HELPAccording to the website Space.com, the distance from the Sun to the Earth is 149,597,870,700 meters and the speed of light is 299,792 kilometers pe