Answer:
QT = 8
Step-by-step explanation:
the sides of a rhombus are congruent , then
PS = RS ( substitute values )
3y - 1 = 2y + 3 ( subtract 2y from both sides )
y - 1 = 3 ( add 1 to both sides )
y = 4
The diagonals of a rhombus bisect each other
QS = 5y - 4 = 5(4) - 4 = 20 - 4 = 16
then
QT = [tex]\frac{1}{2}[/tex] QS = [tex]\frac{1}{2}[/tex] × 16 = 8
