Answer:
(1, 0 )
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex] , then
y = [tex]log_{3}[/tex] (x + 2) - 1
to find the zero let y = 0 , that is
[tex]log_{3}[/tex] (x + 2) - 1 = 0 ( add 1 to both sides )
[tex]log_{3}[/tex] (x + 2) = 1 , then
x + 2 = [tex]3^{1}[/tex] = 3 ( subtract 2 from both sides )
x = 1
the zero is (1, 0 )
