Answer:
[tex]\fbox{8a+10 = 6}[/tex]
Step-by-step explanation:
[tex]2-3a =4+a[/tex]
Adding 3a both side,
[tex]2 - \cancel{3a} + \cancel{3a} =4+a + 3a[/tex]
[tex]2 = 4 + 4a[/tex]
Subtracting 4 from both the side,
[tex]2 - 4 = \cancel4 - \cancel4 + 4a[/tex]
[tex]4a = - 2[/tex]
Now we have to find the value of 8a+10,
[tex]8a+10 = 2(4a) + 10[/tex]
[tex]8a+10 = 2 \times ( - 2) + 10 \\ 8a+10 = - 4 + 10 \\ \fbox{8a+10 = 6}[/tex]
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